125/25^-3m=25^-2m-2

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Solution for 125/25^-3m=25^-2m-2 equation:



125/25^-3m=25^-2m-2
We move all terms to the left:
125/25^-3m-(25^-2m-2)=0
We get rid of parentheses
-3m+2m+2-25^+125/25^=0
We multiply all the terms by the denominator
-3m*25^+2m*25^+125+2*25^-25^*25^=0
We add all the numbers together, and all the variables
-3m*25^+2m*25^=0
Wy multiply elements
-75m^2+50m^2=0
We add all the numbers together, and all the variables
-25m^2=0
a = -25; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-25)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{-50}=0$

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